allow sorting by multiple columns and descending order

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This commit is contained in:
Gregor Aisch 2013-04-02 13:17:30 +02:00
parent adc5d32012
commit 4d503f42e3
1 changed files with 13 additions and 2 deletions
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15
dataset/persistence/table.py
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@ -142,6 +142,12 @@ class Table(object):
return None
return res[0]
def _args_to_order_by(self, order_by):
if order_by[0] == '-':
return self.table.c[order_by[1:]].desc()
else:
return self.table.c[order_by].asc()
def find(self, _limit=None, _step=5000, _offset=0,
order_by='id', **filter):
"""Performs a simple search on the table.
@ -151,11 +157,16 @@ class Table(object):
results = table.find(country='France', year=1980)
# just return the first 10 rows
results = table.find(country='France', _limit=10)
# sort results by a column
# sort results by a column 'year'
results = table.find(country='France', order_by='year')
# return all rows sorted by multiple columns (by year in descending order)
results = table.find(order_by=['country', '-year'])
For more complex queries, please use :py:meth:`db.query() <dataset.Database.query>` instead."""
order_by = [self.table.c[order_by].asc()]
if isinstance(order_by, (str, unicode)):
order_by = [order_by]
order_by = [self._args_to_order_by(o) for o in order_by]
args = self._args_to_clause(filter)
for i in count():